BlinCT
BlinCTJan. 3, 2017, 3:02 a.m.

Поиск максимальных чисел в QPointF

#Qt

Всем привет. Проблема состоит в том каким подходом воспользоватся при поиске максимальных чисел. В хедере есть 2 переменные float m_maxX; float m_maxY; Мы их должны получить в конструкторе из point.

SimpleStandCalculator::SimpleStandCalculator(const PointList &points): m_points(points)
{
    int pointsLeft = 0;     // number of points in the left part
    double x_sum, y_sum;
    x_sum = y_sum = 0.0;

    foreach(const QPointF point, m_points) {
        if(point.x() < 0.0)
            pointsLeft++;
        x_sum += point.x();
        y_sum += point.y();
    m_maxX = ?;
    m_maxY = ?;
    }
    const float fCount = (float)m_points.length();
    m_avg_x = x_sum/fCount;
    m_avg_y = y_sum/fCount;
}
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1
Evgenii Legotckoi
  • Jan. 3, 2017, 4:10 a.m.
  • The answer was marked as a solution.

Привет!
Нужно тогда вначале их обнулить. А потом уже выбирать максимальное число из переменных m_maxX и m_maxY с помощью шаблонной функции qMax() .

SimpleStandCalculator::SimpleStandCalculator(const PointList &points): m_points(points)
{
    int pointsLeft = 0;     // number of points in the left part
    double x_sum, y_sum;
    x_sum = y_sum = 0.0;
    m_maxX = 0.0;
    m_maxY = 0.0;

    foreach(const QPointF point, m_points) {
        if(point.x() < 0.0)
            pointsLeft++;
        x_sum += point.x();
        y_sum += point.y();
    m_maxX = qMax(m_maxX, point.x());
    m_maxY = qMax(m_maxY, point.y());
    }
    const float fCount = (float)m_points.length();
    m_avg_x = x_sum/fCount;
    m_avg_y = y_sum/fCount;
}

Единственный момент, который хотелось бы уточнить, так это то, что имеются ли в данном случае точки с отрицательными координатами и нужно ли выбирать максимальное число по модулю от числа, поскольку по модулю отрицательное число может быть больше чем положительное.

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