BlinCT
BlinCTJune 1, 2019, 9:20 a.m.

Замена define на enum

C++11

Всем привет. Есть такая необходимость уйти в одной реализации с использования define на эти параметры завернутые в enum

#define SG_IO_USE_DETECT 0
#define SG_IO_UNSUPP 1
#define SG_IO_USE_V3 3
#define SG_IO_USE_V4 4

static int sg_io_state = SG_IO_USE_DETECT;

switch (sg_io_state)
{
  case SG_IO_USE_DETECT:
    if ()
    {
      sg_io_state = SG_IO_USE_V3;
      return 0;
    }
    if ()
    {
      sg_io_state = SG_IO_USE_V4;
      return 0;
    }
    sg_io_state = SG_IO_UNSUPP;
  case SG_IO_USE_V3:
  case SG_IO_USE_V4:
    return sg_io_cmnd_io(dev_fd, iop, report, sg_io_state);
  default:
}

Так выглядит то что я хочу переделать, как видно тут просто по всем defines проходит switch и в определенных случаях выставляет значение другого define.

enum class E_SG_IO : unsigned int
    {
        E_SG_IO_USE_DETECT  = 0,
        E_SG_IO_UNSUPP      = 1,
        E_SG_IO_USE_V3      = 3,
        E_SG_IO_USE_V4      = 4
    };

auto eSgIo = E_SG_IO::E_SG_IO_USE_DETECT;

switch (eSgIo)
{
  case E_SG_IO::E_SG_IO_USE_DETECT:
    if ()
    {
      eSgIo = E_SG_IO::E_SG_IO_USE_V3;
      return 0;
    }
    if ()
    {
      eSgIo = E_SG_IO::E_SG_IO_USE_V4;
      return 0;
    }
    eSgIo = E_SG_IO::E_SG_IO_UNSUPP;
  case E_SG_IO::E_SG_IO_UNSUPP:
    return sisc_cmnd_io(dev_fd, iop, report);
  case E_SG_IO::E_SG_IO_USE_V3:
  case E_SG_IO::E_SG_IO_USE_V4:
    return 1;
  default:

Вот моя реализация, что то не правильно сделал, потому что вглубь switch я попасть не могу. Буду признателен за указание моей ошибки.
Спасибо.

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1
BlinCT
  • June 2, 2019, 7:03 a.m.
  • The answer was marked as a solution.

Решение найдено. Вопрос закрыт.

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