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Дмитрий ЧерноволSept. 10, 2021, 10:17 a.m.
Вызов функции Python с Qml
Всем здравствуйте.
Незамысловатая задача появилась у меня - вызвать функцию Python с Qml.
Смотрел уроки на этом сайте, но что-то я не понимаю. Сверял код Qt C++, вроде как всё также, но не работает и прошу помощи у вас
Вот код:
main.py
# This Python file uses the following encoding: utf-8 from PySide2.QtGui import QGuiApplication from PySide2.QtQml import QQmlApplicationEngine from PyQt5.QtCore import QObject, pyqtSignal, pyqtSlot from bs4 import BeautifulSoup import sys import os import requests import time s = requests.Session() class Calculator(QObject): def __init__(self): QObject.__init__(self) takeFunc = pyqtSignal() @pyqtSlot() def result(self, text): while True: t=s.get("http://v.meni.mobi") soup = BeautifulSoup(t.text, 'html.parser') self.text=soup.find("div", class_="footer_share").find("a").get("href") print(text) time.sleep(1) if __name__ == "__main__": app = QGuiApplication(sys.argv) engine = QQmlApplicationEngine() calculator = Calculator() engine.rootContext().setContextProperty("calculator", calculator) engine.load(os.path.join(os.path.dirname(__file__), "main.qml")) if not engine.rootObjects(): sys.exit(-1) sys.exit(app.exec_())
main.qml
import QtQuick 2.15 import QtQuick.Window 2.15 import QtQuick.Extras 1.4 import QtQuick.Controls 2.3 Window { width: 640 height: 480 visible: true title: qsTr("Hello World") Connections { target: calculator // Обработчик сигнала сложения onResult: { } } Button { id: button x: 207 y: 167 text: qsTr("Button") onClicked: calculator.result } }
При компиляции такие ошибки ползут:
Буду очень благодарен советам или помощи
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Игорь МаксимовOct. 3, 2024, 4:05 p.m.
Чтобы onResult в QML подключилось к чему-то в Python, нужно чтобы result было сигналом, а у вас это слот.
В качестве сигнала определено takeFunc и в данном случае в QML должно работать так