Решение "Add Two Numbers" на Leet Code
- /**
- * Definition for singly-linked list.
- * struct ListNode {
- * int val;
- * ListNode *next;
- * ListNode() : val(0), next(nullptr) {}
- * ListNode(int x) : val(x), next(nullptr) {}
- * ListNode(int x, ListNode *next) : val(x), next(next) {}
- * };
- */
- class Solution {
- public:
- ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
- bool isOverheaded = false;
- int sum = 0;
- ListNode* head = new ListNode();
- ListNode* current = head;
- ListNode* currentL1 = l1;
- ListNode* currentL2 = l2;
- while (currentL1 != nullptr || currentL2 != nullptr)
- {
- if (!(currentL1 == l1 && currentL2 == l2))
- {
- current->next = new ListNode();
- current = current->next;
- }
- sum = 0;
- if (currentL1)
- {
- sum += currentL1->val;
- currentL1 = currentL1->next;
- }
- if (currentL2)
- {
- sum += currentL2->val;
- currentL2 = currentL2->next;
- }
- if (isOverheaded)
- {
- ++sum;
- }
- isOverheaded = sum > 9;
- if (isOverheaded)
- {
- current->val = sum % 10;
- }
- else
- {
- current->val = sum;
- }
- }
- if (isOverheaded)
- {
- current->next = new ListNode(1);
- }
- return head;
- }
- };